Q. A student secures 23% marks in an examination but fails by 36 marks. Another student secures 35% marks which are 48 marks more than the required to pass. What is the percentage of marks and marks required to pass?
TLT: Let, Total Marks= 100%
35% – 23% = (48+36)
i.e. 12% = 84
So, 100%= 84/12 X 100
= 700 Total
Pass Marks= 700 X 23/100 + 36
= 161+36 =197